Post, Freight and Carriers

How would I figure this out? (#3)?

This is one of three sample questions for the CHSPE that I need help with. Could you tell me how I would figure this out, in laymen's terms? Each day a freight train leaves Lake City and travels to Hilltown, Chester, and Freeburg. Th en it returns to Lake City. Th e train’s route forms a trapezoid with a right angle as shown below. Here's the image: http://i36.tinypic.com/mrwili.jpg Which is closest to the distance in miles from Freeburg to Lake City? A. 51 B. 43.8 C. 39 D. 32.7

Public Comments

1. First you must pretend there is a point on the road from freeburg to chester that is exactly south of lake city. Now this point is 15 miles from freeburg(120-105) and 36 miles from lake city(the same distance from hilltown to chester). Now use the pythagerean theorem 15^2+36^2=x^2 x=39
2. The triangle at Freeburg is right the base is 120-105 and altitude is 36 the hypotenuse (the distance in question) is ^/(15^2+36^2) or 39 C